3x^2=23x=14

Solution for 3x^2=23x=14 equation:

3x^2=23x=14

We move all terms to the left:

3x^2-(23x)=0

a = 3; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·3·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*3}=\frac{46}{6}
=7+2/3
$